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9x^2-79x+112=0
a = 9; b = -79; c = +112;
Δ = b2-4ac
Δ = -792-4·9·112
Δ = 2209
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$$\sqrt{\Delta}=\sqrt{2209}=47$$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-79)-47}{2*9}=\frac{32}{18} =1+7/9 $$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-79)+47}{2*9}=\frac{126}{18} =7 $
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